How to Solve the Palindrome Array Problem

Welcome to this tutorial where we’ll delve into solving the Palindrome Array problem. In this challenge, you’re given an integer array and your task is to determine if all the elements in the array are palindromes.

Understanding the Problem:

Let’s break down the problem statement:

• You’re given an array A[] of n elements.
• Your function, PalinArray, should return 1 if all the elements in the array are palindromes. Otherwise, it should return 0.

What is a Palindrome?

A palindrome is a number that reads the same forwards and backward. For example, 121, 12321, and 1331 are palindromes.

Approach to Solution:

To solve this problem, we need to check each number in the array to see if it’s a palindrome. If all numbers pass the palindrome test, we return 1; otherwise, we return 0.

Let’s Dive into the Solution:

We’ll write a function called PalinArray that takes an array of integers as input. Here’s a step-by-step approach to implementing this function:

1. Iterate through each element in the array.
2. For each element, convert it to a string so we can check if it’s a palindrome.
3. Check if the string representation of the number is the same when read forwards and backward.
4. If any number fails the palindrome test, return 0.
5. If all numbers pass the test, return 1.

Implementation(Python):

PalinArray(arr):
    for num in arr:
        if str(num) != str(num)[::-1]:
            return 0
    return 1

# Example usage:
arr1 = [111, 222, 333, 444, 555]
arr2 = [121, 131, 20]

print(PalinArray(arr1))  # Output: 1
print(PalinArray(arr2))  # Output: 0
Explanation:

• In the first example, all elements in the array are palindromes, so the function returns 1.
• In the second example, the number 20 is not a palindrome, so the function returns 0.

Conclusion:

You’ve now learned how to solve the Palindrome Array problem. By iterating through each element and checking if it’s a palindrome, you can efficiently determine if all numbers in the array meet the criteria. Happy coding!